The syntax of the decrementExact() method is:
Math.decrementExact(num)
Here, decrementExact() is a static method. Hence, we are accessing the method using the class name, Math.
decrementExact() Parameters
The decrementExact() method takes a single parameter.
- num - argument from which 1 is subtracted
Note: The data type of the argument should be either int or long.
decrementExact() Return Value
- returns the value after subtracting 1 from the argument
Example 1: Java Math.decrementExact()
class Main {
public static void main(String[] args) {
// create a int variable
int a = 65;
// decrementExact() with the int argument
System.out.println(Math.decrementExact(a)); // 64
// create a long variable
long c = 52336L;
// decrementExact() with the long argument
System.out.println(Math.decrementExact(c)); // 52335
}
}
In the above example, we have used the Math.decrementExact() method with the int and long variables to subtract 1 from the respective variables.
Example 2: Math.decrementExact() Throws Exception
The decrementExact() method throws an exception if the result of the subtraction overflows the data type. That is, the result should be within the range of the data type of specified variables.
class Main {
public static void main(String[] args) {
// create a int variable
// minimum int value
int a = -2147483648;
// decrementExact() with the int argument
// throws exception
System.out.println(Math.decrementExact(a));
}
}
In the above example, the value of a is the minimum int value. Here, the decrementExact() method subtracts 1 from a.
a - 1
=> -2147483648 - 1
=> -2147483649 // out of range of int type
Hence, the decrementExact() method throws the integer overflow exception.