The reduce()
method executes a reducer function on each element of the array and returns a single output value.
Example
const message = ["JavaScript ", "is ", "fun."];
// function to join each string elements
function joinStrings(accumulator, currentValue) {
return accumulator + currentValue;
}
// reduce join each element of the string
let joinedString = message.reduce(joinStrings);
console.log(joinedString);
// Output: JavaScript is fun.
reduce() Syntax
The syntax of the reduce()
method is:
arr.reduce(callback(accumulator, currentValue), initialValue)
Here, arr is an array.
reduce() Parameters
The reduce()
method takes in:
- callback - The function to execute on each array element (except the first element if no initialValue is provided). It takes in
- accumulator - It accumulates the callback's return values.
- currentValue - The current element being passed from the array.
- initialValue (optional) - A value that will be passed to
callback()
on first call. If not provided, the first element acts as the accumulator on the first call andcallback()
won't execute on it.
Note: Calling reduce()
on an empty array without initialValue will throw TypeError
.
reduce() Return Value
- Returns the single value resulting after reducing the array.
Notes:
reduce()
executes the given function for each value from left to right.reduce()
does not change the original array.- It is almost always safer to provide
initialValue
.
Example 1: Sum of All Values of Array
const numbers = [1, 2, 3, 4, 5, 6];
function sum_reducer(accumulator, currentValue) {
return accumulator + currentValue;
}
let sum = numbers.reduce(sum_reducer);
console.log(sum); // 21
// using arrow function
let summation = numbers.reduce(
(accumulator, currentValue) => accumulator + currentValue
);
console.log(summation); // 21
Output
21 21
Example 2: Subtracting Numbers in Array
const numbers = [1800, 50, 300, 20, 100];
// subtract all numbers from first number
// since 1st element is called as accumulator rather than currentValue
// 1800 - 50 - 300 - 20 - 100
let difference = numbers.reduce(
(accumulator, currentValue) => accumulator - currentValue
);
console.log(difference); // 1330
const expenses = [1800, 2000, 3000, 5000, 500];
const salary = 15000;
// function that subtracts all array elements from given number
// 15000 - 1800 - 2000 - 3000 - 5000 - 500
let remaining = expenses.reduce(
(accumulator, currentValue) => accumulator - currentValue,
salary
);
console.log(remaining); // 2700
Output
1330 2700
This example clearly explains the difference between passing an initialValue and not passing an initialValue.
Example 3: Remove Duplicate Items from Array
let ageGroup = [18, 21, 1, 1, 51, 18, 21, 5, 18, 7, 10];
let uniqueAgeGroup = ageGroup.reduce(function (accumulator, currentValue) {
if (accumulator.indexOf(currentValue) === -1) {
accumulator.push(currentValue);
}
return accumulator;
}, []);
console.log(uniqueAgeGroup); // [ 18, 21, 1, 51, 5, 7, 10 ]
Output
[ 18, 21, 1, 51, 5, 7, 10 ]
Example 4: Grouping Objects by a property
let people = [
{ name: "John", age: 21 },
{ name: "Oliver", age: 55 },
{ name: "Michael", age: 55 },
{ name: "Dwight", age: 19 },
{ name: "Oscar", age: 21 },
{ name: "Kevin", age: 55 },
];
function groupBy(objectArray, property) {
return objectArray.reduce(function (accumulator, currentObject) {
let key = currentObject[property];
if (!accumulator[key]) {
accumulator[key] = [];
}
accumulator[key].push(currentObject);
return accumulator;
}, {});
}
let groupedPeople = groupBy(people, "age");
console.log(groupedPeople);
Output
{ '19': [ { name: 'Dwight', age: 19 } ], '21': [ { name: 'John', age: 21 }, { name: 'Oscar', age: 21 } ], '55': [ { name: 'Oliver', age: 55 }, { name: 'Michael', age: 55 }, { name: 'Kevin', age: 55 } ] }
Recommended Reading: JavaScript Array reduceRight()