Function Prototype of isdigit()
int isdigit( int arg );
Function isdigit() takes a single argument in the form of an integer and returns the value of type int
.
Even though, isdigit() takes integer as an argument, character is passed to the function. Internally, the character is converted to its ASCII value for the check.
It is defined in <ctype.h> header file.
C isdigit() Return value
Return Value | Remarks |
---|---|
Non-zero integer ( x > 0 ) | Argument is a numeric character. |
Zero (0) | Argument is not a numeric character. |
Example: C isdigit() function
#include <stdio.h>
#include <ctype.h>
int main()
{
char c;
c='5';
printf("Result when numeric character is passed: %d", isdigit(c));
c='+';
printf("\nResult when non-numeric character is passed: %d", isdigit(c));
return 0;
}
Output
Result when numeric character is passed: 1 Result when non-numeric character is passed: 0
Example: C Program to Check whether a Character Entered by User is Numeric Character or Not
#include <stdio.h>
#include <ctype.h>
int main()
{
char c;
printf("Enter a character: ");
scanf("%c",&c);
if (isdigit(c) == 0)
printf("%c is not a digit.",c);
else
printf("%c is a digit.",c);
return 0;
}
Output
Enter a character: 8 8 is a digit.